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Настоящий дипломный проект посвящен обеспечению безопасной работы звеньев газодымозащитной службы, для успешного выполнения поставленной боевой задачи в условиях непригодной для дыхания среды. Результатом для данной работы является разработанная модель обеспечения безопасности звена ГДЗС в НДС на основе математической модели управления процессом безопасности.
This diploma project is dedicated to ensuring the safe operation of the gas-smoke protection service units, for the successful implementation of the combat mission in an unsuitable environment for breathing. The result of this work is the developed model of ensuring the security of the GDZS link in the VAT on the basis of a mathematical model of security process management.
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Table of Contents
- ГЛАВА 2. РАЗРАБОТКА МОДЕЛИ УПРАВЛЕНИЯ ПРОЦЕССОМ ОБЕСПЕЧЕНИЯ БЕЗОПАСНОСТИ ЗВЕНА ГАЗОДЫМОЗАЩИТНОЙ СЛУЖБЫ ПРИ РАБОТЕ В НЕ ПРИГОДНОЙ ДЛЯ ДЫХАНИЯ СРЕДЕ
- 2.4 значение Синтез модели управления безопасностью
- 3.2. Разработка сетевой модели целевого процессазвена газодымозащитной службы в непригодной для дыхания среде, образования, распознования и устранения угрозы
- 3.2.1. Разработка сетевой модели проведения аварийноспасательних работ звеном ГДЗС в непригодной для дыхания среде.
- (3.15)
- Rп(0,1) = 10-5-0 = 5
- Rп(0,2) = 20-10-0 = 10
- Rп(0,3) = 10-10-0 = 0
- Rп(0,4) = 10-0-0 = 10
- Rп(1,5) = 36-10-5 = 21
- Rп(1,6) = 36-16-5 = 15
- Rп(1,7) = 36-10-5 = 21
- Rп(2,8) = 36-25-10 = 1
- Rп(2,9) = 36-25-10 = 1
- Rп(2,10) = 36-14-10 = 12
- Rп(2,11) = 36-26-10 = 0
- Rп(3,12) = 36-18-6 = 12
- Rп(3,13) = 36-30-6 = 0
- Rп(3,14) = 36-26-6 = 4
- Rп(3,15) = 36-20-6 = 10
- Rп(3,16) = 36-14-6 = 16
- Rп(4,17) = 36-10-10 = 16
- Rп(4,18) = 36-14-10 = 12
- Rп(4,19) = 36-25-10 = 1
- Rп(4,20) = 36-8-10 = 18
- Rп(4,21) = 36-17-10 = 9
- Rп(8,24) = 38-25-10 = 2
- Rп(9,24) = 38-25-10 = 3
- Rп(5,24) = 38-10-10 = 18
- Rп(6,24) = 38-16-10 = 12
- Rп(7,24) = 38-10-10 = 18
- Rп(10,24) = 38-14-6 = 18
- Rп(11,24) = 38-26-10 =2
- Rп(12,24) = 38-18-6 = 14
- Rп(13,22) = 36-30-6 = 0
- Rп(13,23) = 36-30-6 = 0
- Rп(13,24) = 38-2-36 = 0
- Rп(14,24) = 38-26-10 = 2
- Rп(15,24) = 38-20-10 = 10
- Rп(16,24) = 38-14-6 = 18
- Rп(17,24) = 38-10-6 = 22
- Rп(18,24) = 38-14-10 = 14
- Rп(19,24) = 38-25-10 = 3
- Rп(20,24) = 38-8-10 = 20
- Rп(21,24) = 38-17-10 = 11
- Rп(22,24) = 38-30-6 = 2
- Rп(23,24) = 38-30-8 = 0
- Rп(24,25) = 39-1-38 = 0
- RC(10,24) =22-14-5=3 RC(11,24) =22-15-5=2 RC(12,24) =22-15-5=2 RC(13,22) =17-15-2=0 RC(13,23) =16-15-1=0 RC(13,24) =22-15-5=2 RC(14,24) =22-13-5=4 RC(15,24) =22-12-5=5 RC(16,24) =22-14-5=3 RC(17,24) =22-10-5=7 RC(18,24) =22-10-5=7 RC(19,24) =22-10-5=7 RC(20,24) =22-7-5=10 RC(21,24) =22-10-5=7 RC(22,24) =22-17-5=0 RC(23,24) =22-16-5=5 RC(24,25) = 24-2-22 = 0
- (3.23)
- Rп(0,1) = 10-5-0 = 5
- Rп(0,2) = 20-10-0 = 10
- Rп(0,3) = 10-10-0 = 0
- Rп(0,4) = 10-0-0 = 10
- Rп(1,5) = 36-10-5 = 21
- Rп(1,6) = 36-16-5 = 15
- Rп(1,7) = 36-10-5 = 21
- Rп(2,8) = 36-25-10 = 1
- Rп(2,9) = 36-25-10 = 1
- Rп(2,10) = 36-14-10 = 12
- Rп(2,11) = 36-26-10 = 0
- Rп(3,12) = 36-18-6 = 12
- Rп(3,13) = 36-30-6 = 0
- Rп(3,14) = 36-26-6 = 4
- Rп(3,15) = 36-20-6 = 10
- Rп(3,16) = 36-14-6 = 16
- Rп(4,17) = 36-10-10 = 16
- Rп(4,18) = 36-14-10 = 12
- Rп(4,19) = 36-25-10 = 1
- Rп(4,20) = 36-8-10 = 18
- Rп(4,21) = 36-17-10 = 9
- Rп(8,24) = 38-25-10 = 2
- Rп(9,24) = 38-25-10 = 3
- Rп(5,24) = 38-10-10 = 18
- Rп(6,24) = 38-16-10 = 12
- Rп(7,24) = 38-10-10 = 18
- Rп(10,24) = 38-14-6 = 18
- Rп(11,24) = 38-26-10 =2
- Rп(12,24) = 38-18-6 = 14
- Rп(13,22) = 36-30-6 = 0
- Rп(13,23) = 36-30-6 = 0
- Rп(13,24) = 38-2-36 = 0
- Rп(14,24) = 38-26-10 = 2
- Rп(15,24) = 38-20-10 = 10
- Rп(16,24) = 38-14-6 = 18
- Rп(17,24) = 38-10-6 = 22
- Rп(18,24) = 38-14-10 = 14
- Rп(19,24) = 38-25-10 = 3
- Rп(20,24) = 38-8-10 = 20
- Rп(21,24) = 38-17-10 = 11
- Rп(22,24) = 38-30-6 = 2
- Rп(23,24) = 38-30-8 = 0
- Rп(24,25) = 39-1-38 = 0
- RC(10,24) =22-14-5=3 RC(11,24) =22-15-5=2 RC(12,24) =22-15-5=2 RC(13,22) =17-15-2=0 RC(13,23) =16-15-1=0 RC(13,24) =22-15-5=2 RC(14,24) =22-13-5=4 RC(15,24) =22-12-5=5 RC(16,24) =22-14-5=3 RC(17,24) =22-10-5=7 RC(18,24) =22-10-5=7 RC(19,24) =22-10-5=7 RC(20,24) =22-7-5=10 RC(21,24) =22-10-5=7 RC(22,24) =22-17-5=0 RC(23,24) =22-16-5=5 RC(24,25) = 24-2-22 = 0
- (3.28)
- Rп(0,1) = 25-10-0 = 15 Rп(0,2) = 23-15-0 = 8
- Rп(0,3) = 18-10-0 = 8 Rп(2,9) = 23-15-3 = 5
- Rп(2,10) = 23-15-5 = 3 Rп(3,11) = 18-10-3 = 5
- Rп(3,12) = 18-10-8 = 0 Rп(3,13) = 18-10-5 = 3
- Rп(3,14) = 18-10-8 = 0 Rп(4,15) = 21-8-5 = 8
- Rп(4,16) = 21-8-2 = 11 Rп(4,17) = 21-8-6 = 7
- Rп(4,18) = 21-8-3 = 10 Rп(4,19) = 21-8-5 = 8
- Rп(5,22) = 33-15-2 =16 Rп(6,22) = 33-15-2 = 16
- Rп(7,22) = 33-15-4 = 14 Rп(8,22) = 33-15-5 = 13
- Rп(9,20) = 28-3-10 = 15 Rп(9,21) = 28-18-10 = 0
- Rп(10,22) = 33-15-5 = 13 Rп(11,22) = 33-15-3 = 15
- Rп(12,22) = 33-15-8 = 10 Rп(13,22) = 33-15-5 = 13
- Rп(14,22) = 33-15-8 = 10 Rп(15,22) = 33-15-5 = 13
- Rп(16,22) = 33-15-2 = 16 Rп(17,22) = 33-15-6 = 12
- Rп(18,22) = 33-15-3 = 15 Rп(19,22) = 33-15-5 = 13
- Rп(20,22) = 33-15-10 = 8 Rп(21,22) = 33-15-10 = 8
- Rп(22,23) = 43-10-33 = 0 Rп(23,24) = 53-10-43 = 0
- Резерв свободного времени каждой из работ заключается в задержке в выполнения задания на величину ∆tij≤rC(i,j), не имея влияния ни на один из сроков, который определен описанным сетевым графиком[12]
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